@kvvaradha - Thank you for such a quick reply! So, to try to answer your questions, I will list below what and how I started this database:
1. I am the System Administrator of the 1and1.com MySQL databases version 5.5.60-0+deb7u1-log, PHP version 7.1.20, Http server type Apache, Server system Linux. The database was created new and empty online through the 1and1.com Dashboard MySQL Database control panel. Setup username and password and initialized at 1024 of 1024 MB available.
2. I then created at my root access of the hosting site a directory named xxyyzz and unzipped the tar file to it. Using a Chrome browser on my Windows10 x64 pc, went to the url of my site: https://mycompany.co/xxyyzz which immediately went into the FA installation wizard. The wizard completed with absolutely no warnings or errors including the input of me, jimmyc, as Administrator, setting up my password and DB location/password, etc.
3. Logging into FA the first time I chose to use the US COA for a nonprofit company for the initial opening and immediately went into the Setup tab => Access Setup => System Administrator and enabled every single item in the list. But, I noticed when I am in FA, the top left corner shows "MycompanyName | mycompany.co | Administrator", not "System Administrator".
4. So before I began this post, I logged into my FA on my website and captured the sql_trail just for this login. It is attached in the csv format and it shows that FA "could not get validate user login for jimmyc".
Finally, I wish to point out that the install and creation of this MySQL DB was done within about one hours time yesterday. This was to narrow down why I am getting these errors. I have a "similar" installation done March 28, 2018 with thousands of records already entered and the sql_trail of that database is where I had first noticed these problems.
I hope you can help me solve my problem, which I am beginning to think it is caused by "could not get validate user login for jimmyc". Please note that in my attached file, I did change the password string to "xxxxxxxxxxxx".